multiply (3y²-5)by(5y²-3y+1) and verify the result for y =0
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2
Answer:\
Given that,
y =0
Then,
(3y²-5) × (5y²-3y+1)
= (3×0²-5) × (5×0²-3×0+1)
= (-5) × 1
= (-5)
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