Question

Multiply 4 - 2y + 6y^2 - 7y^3 by 3y - 1 + y^3 - y^2​

Answer 1

Answer:

-7y^6+13y^5-29y^4+31y^3-16y^2+14y-4

Answer 2

Answer:

The product after multiplication is $-7y^6+13y^5-29y^4+31y^3-16y^2+14y-4$.

Step-by-step explanation:

Given equations are $4-2y+6y^2-7y^3$ and $3y-1+y^3-y^2$.

When multiplying two equations like above, we use distributive property of multiplication.

We take second term as a single term and multiply with the first term using distributive property.

$(4-2y+6y^2-7y^3)(3y-1+y^3-y^2)$

$=4(3y-1+y^3-y^2)-2y(3y-1+y^3-y^2)+6y^2(3y-1+y^3-y^2)-7y^3(3y-1+y^3-y^2)$

$=12y-4+4y^3-4y^2-6y^2+2y-2y^4+2y^3+18y^3-6y^2+6y^5-6y^4-21y^4+7y^3-7y^6+7y^5$

$=-7y^6+13y^5-29y^4+31y^3-16y^2+14y-4$

After multiplication, the final product is $-7y^6+13y^5-29y^4+31y^3-16y^2+14y-4$.