Question

Multiply: (4/3 x sq yz) × (1/3 y sq zx) × (-6xyz sq)

Answer 1

$\frac{4}{3} x^{2}yz \times \frac{1}{3}y^{2}zx \times ( -6xyz^{2})$

$= \frac{4}{3}\times \frac{1}{3}\times (-6) x^{2}\times x \times x \times y \times y \times y^{2} \times z \times z \times z^{2}$

$= \frac{-8}{3} x^{2+1+1} \times y^{1+2+1} \times z^{1+1+2}$

$= \frac{-8}{3} x^{4} \times y^{4} \times z^{4}$

Therefore.,

$\red{ \frac{4}{3} x^{2}yz \times \frac{1}{3}y^{2}zx \times ( -6xyz^{2})}$

$\green{ = \frac{-8}{3} x^{4} \times y^{4} \times z^{4}}$

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