Question

multiply (4-3x)(2×^2-13x+15)​

Answer 1

$\mathtt{\huge{\underline{\red{Correct\:Question\:?}}}}$

⭐ (4 - 3x) (2x² - 13x + 15)

$\mathtt{\huge{\underline{\green{Answer:-}}}}$

✒ - 6 x³ + 47 x² - 7 x + 60

$\mathtt{\huge{\underline{\purple{Concept:-}}}}$

➡ Polynomial an expression consist of two or more terms of algebra.

It consist of 3 parts :-

• Constant

• Variable

• Exponent

The polynomials of three types are :-

• Monomial :- Polynomial of degree 1.

eg. 4 ,y, 8x

• Binomial :- Polynomial of degree 2.

eg. 2x+y, a²x+by

• Trinomial :- Polynomial of degree 3.

eg. ax³+x + k

$\mathtt{\huge{\underline{\orange{Solution:-}}}}$

Given :-

• (4 - 3x) (2x² - 13x + 15)

To Find :-

• Multiply both .

Calculation :-

(4 - 3x) (2x² - 13x + 15)

➝ 8 x² - 52 x + 60 - 6 x³ + 39 x² - 45 x

➝ - 6 x³ + 8 x² + 39 x² - 52 x - 45 x + 60

➝ - 6 x³ + 47 x² - 7 x + 60

So, the answer by multiplying these polynomial 6 x³ + 47 x² - 7 x + 60.

This is the polynomial .

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Answer 2

Answer:

$\huge \star \huge \underline \blue {question \: : }$

$\red {(4 - 3x) \times (2 {x}^{2} - 13x + 15}$

$\huge \star \huge \underline \blue {answer \: : }$

$= 4(2 {x}^{2} - 13x + 15) - 3x(2 {x}^{2} - 13x + 15) \\ \\ = 8 {x}^{2} - 52x + 60 - 6 {x}^{3} + 39 {x}^{2} - 45x \\ \\ = - 6 {x}^{3 } + {8x}^{2} + 39 {x}^{2} - 52x - 45 x + 60 \\ \\ = - 6 {x}^{3} + (8 {x}^{2} + 39 {x}^{2}) - (52 + 45)x + 60 \\ \\ = - 6 {x}^{3} + 47{x}^{2} - 97x + 60 \\ \\ \\ \large \pink{therefore} \\ (4 - 3x)(2 {x}^{2} - 13x + 15) \\ \\ = > - 6 {x}^{3} + 47 {x}^{2} - 97x + 60$

$\huge{\boxed{\mathfrak{Hope \: it \: helps}}}$

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