Question

Multiply -4/3xy³ and 6/7x²y and verify your result for x = 2 and y = 1

Answer 1

$( \frac{ - 4}{3}x {y}^{3} )( \frac{6}{7} {x}^{2}y ) \\ \\ \frac{ - 8}{7} {x}^{3} {y}^{4}$
Now,

$(\frac{ - 8}{7} ) {(2)}^{3}( {1}^{4} ) \\ = \frac{ - 8}{7} \times 8 \times 1 = \frac{ - 64}{7}$

Answer 2

Answer:

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