Question

Multiply-4/3xy3 by 6/7x2yand verify your result for x=2 and y=1​

Answer 1

Answer:

$\frac{ - 4}{3x {y}^{3} } \div \frac{6}{7 {x}^{2}y } \\ = \frac{ - 4}{3(2) {(1)}^{3} } \div \frac{6}{7 {(2)}^{2}(1) } \\ = \frac{4}{6} \div \frac{6}{28} \\ = \frac{4}{6} \times \frac{28}{6} \\ = \frac{28}{9}$