multiply(4 x^2 + 3 y) by ( 3 x^2 -- 4 y) and verify the result f
or x= 1 , y= 2.
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Answer:
hey mate✌
(4x^2+3y)(3x^2-4y)
[4(1)^2+3(2)][3(1)^2-4(2)]
[4+6][3-8]
10×(-5)
-50
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