Question

multiply: 5 - 2a + 6a² by 3a² - 5a + 2

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Answer 1

Please refer to the attachment for your answer

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Answer 2

Answer:

In this Question solution is the value of a is (1,2/3,$\frac{1+\sqrt{29} i}{6}$,$\frac{1-\sqrt{29}i }{6}$)

Explanation: In the Given question is $6a^{2} -2a+5$ and $3x^{2} -5a+2$

if we Multiply these two equation

$(6a^{2}-2a+5 )*( 3a^{2}-5a+2)$

$= (6a^{2}*3a^{2}+6a^{2}*(-5a)+6a^{2}*2) +((-2a)*3a^{2}+(-2a)*(-5a)+(-2a)*2)+(5*3a^{2}+5*(-5a)+5*2)\\=18a^{4}-30a^{3}+12a^{2}-6a^{3}+10a^{2}-4a+15a^{4}-25a+10\\=18a^{4}-36a^{3}+37a^{2}-29a+10\\now here apply \\a^{4}+b^{3}+c^{2}+d+e\\\\formula$

If Your an Engineer Student then  solve these equations by calculator and if Your a student then u apply the formula and solve the equation

the value of a is (1,2/3,$\frac{1+\sqrt{29} i}{6}$,$\frac{1-\sqrt{29}i }{6}$)