Math, asked by umesadafchauhan786, 16 days ago

Multiply : ( 5 + 3y -2x ) and ( 2 + 3x )​

Answers

Answered by Itishika
0

Answer:

(2+3x) (5+3y-2x)

10+6y-4x+15x+9xy-6x²

10+6y+11x+9xy-6x²

Answered by payalchatterje
0

Answer:

Required answer is 10 + 11x + 6y + 9xy - 6 {x}^{2}

Step-by-step explanation:

Given two terms are (5+3y-2x) and (2+3x)

We want to multiply it.

So,

(5 + 3y - 2x) \times (2 + 3x) \\  = 10 + 15x + 6y + 9xy - 4x - 6 {x}^{2}  \\  = 10 + 11x + 6y + 9xy - 6 {x}^{2}

This is a problem of Algebra.

Some important Algebra formulas:

{(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2} \\  {(x  -  y)}^{2}  =  {x}^{2}   -  2xy +  {y}^{2} \\  {(x  + y)}^{3}  =  {x}^{3}  + 3 {x}^{2} y + 3x {y}^{2}  +  {y}^{3}  \\   {(x   -  y)}^{3}  =  {x}^{3}   -  3 {x}^{2} y + 3x {y}^{2}   -  {y}^{3} \\  {x}^{3}  +  {y}^{3}  =  {(x  +  y)}^{3}  - 3xy(x + y) \\ {x}^{3}   -  {y}^{3}  =  {(x   -   y)}^{3}   +  3xy(x  -  y) \\  {x}^{2}  -  {y}^{2}  = (x + y)(x - y) \\    {x}^{2}  +  {y}^{2}  =  {(x - y)}^{2}   + 2xy \\ {x}^{2}   -  {y}^{2}  =  {(x   + y)}^{2}  - 2xy \\  {x}^{3}  -  {y}^{3}  = (x - y)( {x}^{2}  + xy +  {y}^{2} ) \\ {x}^{3}   +   {y}^{3}  = (x - + y)( {x}^{2}   -  xy +  {y}^{2} )

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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