Question

multiply (5-x)(6-5x)*2-x)​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:

$= > (5 - x)( 6 - 5x)(2 - x)$

$= > [5(6 - 5x) - x(6 - 5x](2 - x)$

$= > [30 - 25x - 6x + 5 {x}^{2} ](2 - x)$

$= >[30 - 25x - 6x + 5 {x}^{2} ](2 - x)$

$= > [30 - 31x + 5 {x}^{2} ](2 - x)$

$= > 2(30 - 31x + 5 {x}^{2} ) - x(30 - 31x + 5 {x}^{2} )$

$= > 60 - 62x + 10 {x}^{2} - 30x + 62x - 5 {x}^{3}$

$= - 5 {x}^{3} + 10 {x}^{2} - 30x + 60$

$\bold\fcolorbox{aqua}{orange}{Answer}$$\bold{ - 5 {x}^{3} + 10 {x}^{2} - 30x + 60}$

Answer 2

=>(5−x)(6−5x)(2−x)

= > [5(6 - 5x) - x(6 - 5x](2 - x)=>[5(6−5x)−x(6−5x](2−x)

= > [30 - 25x - 6x + 5 {x}^{2} ](2 - x)=>[30−25x−6x+5x2](2−x)

= > [30 - 25x - 6x + 5 {x}^{2} ](2 - x)=>[30−25x−6x+5x2](2−x)

= > [30 - 31x + 5 {x}^{2} ](2 - x)=>[30−31x+5x2](2−x)

= > 2(30 - 31x + 5 {x}^{2} ) - x(30 - 31x + 5 {x}^{2} )=>2(30−31x+5x2)−x(30−31x+5x2)

= > 60 - 62x + 10 {x}^{2} - 30x + 62x - 5 {x}^{3}=>60−62x+10x2−30x+62x−5x3

= - 5 {x}^{3} + 10 {x}^{2} - 30x + 60=−5x3+10x2−30x+60