Math, asked by thejeshvaradhans, 2 months ago

MULTIPLY 5A+3B+C WITH 2C

Answers

Answered by priyanshs86
0

Step-by-step explanation:

Put the coefficients in a augmented matrix:

a

3

b

+

2

c

=

1

[

1

3

2

1

]

5

a

+

3

b

+

c

=

5

[

1

3

2

1

5

3

1

5

]

14

a

2

b

+

3

c

=

6

1

3

2

1

5

3

1

5

14

2

3

6

Perform row operations, until you get an identity matrix:

1

3

2

1

5

3

1

5

14

2

3

6

Multiply row 1 by -5 and add to row 2:

1

3

2

1

0

18

9

0

14

2

3

6

Multiply row 1 by -14 and add to row 2:

1

3

2

1

0

18

9

0

0

40

25

20

Divide row 2 by 9 and row 3 by 5:

1

3

2

1

0

2

1

0

0

8

5

4

Multiply row 2 by -4 and add to row 3:

1

3

2

1

0

2

1

0

0

0

1

4

Multiply row 3 by -1 and leave it that way after adding to row 2:

1

3

2

1

0

2

0

4

0

0

1

4

Divide row 3 by 2:

1

3

2

1

0

1

0

2

0

0

1

4

Multiply row 3 by -2 and add to row 1:

1

3

0

7

0

1

0

2

0

0

1

4

Multiply row 2 by 3 and add to row 1:

1

0

0

1

0

1

0

2

0

0

1

4

The identity matrix says,

a

=

1

,

b

=

2

,

and

c

=

4

Check:

1

3

(

2

)

+

2

(

4

)

=

1

5

(

1

)

+

3

(

2

)

+

4

=

5

14

(

1

)

2

(

2

)

+

3

(

4

)

=

6

1

=

1

5

=

5

6

=

6

Answered by Anonymous
0

Step-by-step explanation:

2C(5A) + 2C(3B) + 2C(C)

=10CA + 6CB + 2C²

hope it's help you ✌️

@ BJ ❤️

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