Multiply (5x-y)(3x^2+4xy+y^2)and verify the result by taking x=-2and y=2
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Answer:
(5(2) -2) (3(2) ^2+4(2) (2) +(2) ^2)
(10-2) (12+16+4)
(8) (32)
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Step-by-step explanation:
We have
(5x-y)(3x²+4xy+y²)
=> 5x(3x²+4xy+y²)-y(3x²+4xy+y²)
=> (5x×3x²)+(5x×4xy)+(5x×y²)-(y×3x²)-(y×4xy)-(y×y²)
=> 15x³+20x²y+5xy²-3x²y-4xy²-y³
=> 15x³+(20x²y-3x²y)+(5xy²-4xy²)-y³
=> 15x³+17x²y+xy²-y³
(5x-y)(3x²+4xy+y²) = 15x³+17x²y+xy²-y³
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