Math, asked by jugrajaulakh1906, 4 months ago

multiply 5x2 -4x+1 by 2x2+3x -7​

Answers

Answered by Legend42
27

Answer:

[1/(x-3)]+[2/(x-2)]=8/x

Add the left side: (3x-8)/[(x-3)(x-2)]=8/x

Now cross multiply:x(3x-8)=8x2-40x+48

Collect terms: 5x2-32x+48=0

Factor: (5x-12)(x-4)=0

Answered by StrangeStinkle
4

Answer:

assume you mean: [1/(x-3)]+[2/(x-2)]=8/x

Add the left side: (3x-8)/[(x-3)(x-2)]=8/x

Now cross multiply:x(3x-8)=8x2-40x+48

Collect terms: 5x2-32x+48=0

Factor: (5x-12)(x-4)=0

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