multiply 5x2 -4x+1 by 2x2+3x -7
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Answered by
27
Answer:
[1/(x-3)]+[2/(x-2)]=8/x
Add the left side: (3x-8)/[(x-3)(x-2)]=8/x
Now cross multiply:x(3x-8)=8x2-40x+48
Collect terms: 5x2-32x+48=0
Factor: (5x-12)(x-4)=0
Answered by
4
Answer:
assume you mean: [1/(x-3)]+[2/(x-2)]=8/x
Add the left side: (3x-8)/[(x-3)(x-2)]=8/x
Now cross multiply:x(3x-8)=8x2-40x+48
Collect terms: 5x2-32x+48=0
Factor: (5x-12)(x-4)=0
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