multiply 6 X square + X - 1 and x minus 3 the whole cube
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Answered by
0
Hi ,
( 6x² + x - 1 ) ( x - 3 )³
= ( 6x² + x - 1 )( x³ - 9x² + 27x - 27 )
= 6x^5 - 54x⁴ + 162x³ - 162x²
+ x⁴ - 9x³ + 27x² - 27x
- x³ + 9x² - 27x + 27
= 6x^5 - 53x⁴ + 152x³ - 126x² - 54x + 27
I hope this helps you.
: )
( 6x² + x - 1 ) ( x - 3 )³
= ( 6x² + x - 1 )( x³ - 9x² + 27x - 27 )
= 6x^5 - 54x⁴ + 162x³ - 162x²
+ x⁴ - 9x³ + 27x² - 27x
- x³ + 9x² - 27x + 27
= 6x^5 - 53x⁴ + 152x³ - 126x² - 54x + 27
I hope this helps you.
: )
Answered by
1
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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