Multiply 6561 by the smallest number so that product is a perfect cube. Also, find the cube root of that product so obtained.
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So, 6561 = 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3
Then to make 6561 a perfect cube. It should be multiplied by 3 and. hence the required cube root is 3 × 3 × 3 = 27
Then to make 6561 a perfect cube. It should be multiplied by 3 and. hence the required cube root is 3 × 3 × 3 = 27
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Answer:
6561 = 3×3×3×3×3×3×3×3
grouping grouping of the equal factor in 3's , we see that 3 × 3is left ungrouped in 3's, in order to complete it in triplet, we multiply it by 3
hence, required smallest number→3
and cube root of the product→3×3×3
→ 27
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