Math, asked by krishnakumar69049, 9 months ago

Multiply (6x^2-5x+3) by (3x^2+7x-3)

Answers

Answered by aaditya9259

63

Answer:

18x^4+33x^3+26x^2+6x-9

Step-by-step explanation:

6x^2(3x^2+7x-3)-5x(3x^2+7x-3)+3(3x^2+7x-3)

=18x^4+48x^3-18x^2-15x^3+35x^2-15x+9x^2+21x-9

=18x^4+48x^3-15x^3-18x^2+35x^2+9x^2-15x+21x-9

=18x^4+33x^3+26x^2+6x-9

Answered by sunprince0000

18

Answer:

18x^4+33x^3+26x^2+6x-9

Step-by-step explanation:

6x^2(3x^2+7x-3)-5x(3x^2+7x-3)+3(3x^2+7x-3)

=18x^4+48x^3-18x^2-15x^3+35x^2-15x+9x^2+21x-9

=18x^4+48x^3-15x^3-18x^2+35x^2+9x^2-15x+21x-9

=18x^4+33x^3+26x^2+6x-9

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