Question

Multiply 6x^3 - y + 3x^2y by x^2+y^2

Answer 1

Answer:

3x^2y^3+6x^3y^2+3x^4y+6x^5-y^3-x^2y

Step-by-step explanation:

(6x^3 - y + 3x^2y)(x^2+y^2)

it's just multiplying everything by x^2 and y^2 and then adding them it will take too long to write out.

Answer 2

On multiplying (x² + y²) × (6x³ - y + 3x²y) we get

6x⁵-x²y + 3x⁴y + 6x³y² - y³ + 3x²y³  

Given:

6x³ - y + 3x²y and x²+ y²  

To find:

Multiply 6x³ - y + 3x²y and x²+ y²    

Solution:

Formula used:

By the distributive property of multiplication

                    A(B + C) = AB + AC

Using the above formula

(x² + y²) × [6x³ - y + 3x²y]  

=> (x²) × [6x³ - y + 3x²y] + (y²) × [6x³ - y + 3x²y]  

Now simplify the above expression as follows

=> (x²) × [6x³ - y + 3x²y] = 6x⁵ - x²y + 3x⁴y

=> (y²) × [6x³ - y + 3x²y] = 6x³y² - y³ + 3x²y³  

=> (x² + y²) × [6x³ - y + 3x²y]

= 6x⁵ - x²y + 3x⁴y + 6x³y² - y³ + 3x²y³  

Therefore,

On multiplying (x² + y²) × (6x³ - y + 3x²y) we get

6x⁵-x²y + 3x⁴y + 6x³y² - y³ + 3x²y³  

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