Math, asked by sashisadhana, 4 months ago

multiply (8/3+y)(8/3-y) using identities

Answers

Answered by Anonymous

6

Answer:

(y−8)×(3y−4)

=y(3y−4)−8(3y−4)

=3y2−4y−24y+32

=3y2−28y+32

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