Question

multiply -8x and 4 - 2x - x²​

Answer 1

$( - 8x) \times (4 - 2x - {x}^{2} ) \\ \\ = ( - 8x \times 4) - ( - 8x \times 2x) - ( - 8x \times {x}^{2} ) \\ \\ = ( - 32x) - ( - 16 {x}^{2} ) - ( - 8 {x}^{3} ) \\ \\ = - 32x + 16 {x}^{2} + 8 {x}^{3} \\ \\ = 8 {x}^{3} + 16 {x}^{2} - 32x$

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