Question

Multiply (a'2+2c'2)(3a-3c)

Answer 1

Answer:

(a^2 +2c^2) (3a-3c)

a^2(3a-3c) +2c^2(3a-3c)

3a^3-3a^2c+6ac^2-7c^3

therefore we get

3(a^3-a^2c+2ac^2-2c^3)

Answer 2

Answer:

is 3a^3 -2c +2ac2-2c3

Step-by-step explanation:

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