Question

Multiply :




a) (2x + 3)(5x - 6)

b) (-5y - 2)(4y - 1)

c) (2z - 3)(-5z - 6)

d) (3.1k + 6.2)(2.9k + 4.7)

e) (-2a + 3b)(5a - 6b)​

Answer 1

Answer:

a) (2x+3) (5x-6)

(5x) (-1x)

-4x

b) (-5-2) (4y-1)

(5+2) (4y-1)

-7y * 3y

-21ysquare

Answer 2

Answer :-

a) (2x + 3)(5x - 6)

→ 2x * 5x + 2x * (-6) + 3 * 5x + 3 * (-6)

→ 10x² - 12x + 15x - 18

→ 10x² + 3x - 18

b) (-5y - 2)(4y - 1)

→ (-5y) * 4y + (-5y) * (-1) - 2 * 4y - 2 * (-1)

→ -20y² + 5y - 8y + 2

→ -20y² - 3y + 2

c) (2z - 3)(-5z - 6)

→ 2z * (-5z) + 2z * (-6) + (-3) * (-5z) + (-3) * (-6)

→ -10z² - 12z + 15z + 18

→ -10z² + 3z + 18

d) (3.1k + 6.2)(2.9k + 4.7)

→ 3.1k * 2.9k + 3.1k * 4.7 + 6.2*2.9k + 6.2 * 4.7

→ 8.99k² + 14.57k + 17.98k + 29.14

→ 8.99k² + 32.55k + 29.14

e) (-2a + 3b)(5a - 6b)

→ (-2a) * 5a + (-2a) * (-6b) + 3b * 5a + (3b) * (-6b)

→ -10a² + 12ab + 15ab - 18b²

→ -10a² - 28b² + 27ab .

Learn more :-

JEE mains Question :-

https://brainly.in/question/22246812

. Find all the zeroes of the polynomial x4

– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.

https://brainly.in/question/39026698