Math, asked by sachraj14, 11 months ago

 multiply a certain number by 28,add 14 to the product,divide the sum by 13 and subtract 4 from the result.if i obtain twice the original number what number did i take at first​

Answers

Answered by Anonymous
76

Hey Buddy

Here's The Answer

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=> Let support that number be ( x )

A.T.Q

=> multiply a certain number by 28,add 14 to the product,divide the sum by 13 and subtract 4

Equation will be

=>{ [ (28 . x) + 14 ] / 13 } - 4 = 2 x

=> (28x + 14 - 4(13 ))/13 = 2x

BY TAKING LCM

=>( 28x + 14 - 52 )/13 = 2x

=> 28x - 38 = 2x ( 13 )

=> 28x - 38 = 26x

=> 28x - 26x = 38

=> 2x = 38

=> x = 19

Hence the number was 19

Hope Helped

PEACE :)

Answered by pranav2001
47

ATQ

(28x + 14 ) /13 - 4 = 2x

28x + 14 - 52 = 13* 2x

28x - 38 = 26 x

28x - 26x = 38

2x = 38

x = 19


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