Question

Multiply additive inverse of 3/4 and reciprocal of 9/16​

Answer 1

Step-by-step explanation:

$additive \: inverse \: of \: \frac{3}{4} is \: \frac{ - 3}{4} \\ resiprocalof \: \frac{9}{16} \: is \: \frac{16}{9} \\ product \: of \: the \: two \: is \: \\ \\ = \frac{ - 3}{4} \times \frac{16}{9} = \frac{ - 4}{3}$

Answer 2

Answer:

= -4/3

Step-by-step explanation:

The additive inverse of 3/4 is -3/4 and reciprocal of 9/16 is 16/9 so-

= -3/4×16/9

= -4/3

I hope it helps you.