Question

Multiply additive inverse of-7/8

by multiplicative inverse of-7/3​

Answer 1

Hey there! Here is your answer with a complete step-by-step solution

Answer:

The product of the additive inverse of -7/8 and the multiplicative inverse of -7/3 is -3/8

Step-by-step explanation:

Ok so, the additive inverse of any positive integer, turns into a negative integer, for example, the additive inverse of 3/5 is -3/5. Like the positive integers, the additive inverse of any negative integer turns into a positive integer. For example, the additive inverse of -6/5 is 6/5.

So, the additive inverse of -7/8 will be 7/8.

Now, the multiplicative inverse of any fraction changes the numerator into the denominator and the denominator into the numerator but does not change the operation. For example, the multiplicative inverse of -3/7 is -7/3, or the multiplicative inverse of 8/3 is 3/8.

So, the multiplicative inverse of -7/3 is -3/7.

Now, we have got the additive inverse of -7/8 and the multiplicative inverse of -7/3, so now, we just need to multiply both of them.

= $\frac{7}{8} x \frac{3}{8}$

= $-\frac{3}{8}$

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