Question

multiply and verify the result for given values:(x+y)(8x-y);x=1,y=0​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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$(x + y)(8x - y) \\ = x(8x - y) + y(8x - y) \\ = 8 {x}^{2} - xy + 8xy - {y}^{2} \\ 8 {x}^{2} + 7xy - {y}^{2} \\ = 8 {(1)}^{2} + 7 \times 1 \times 0 - {0}^{2} \\ = 8$