multiply ax+3 and ax-3 by using formula
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(ax + 3)(ax - 3)
Keeping (ax - 3) common
= ax (ax - 3) + 3 (ax - 3)
= a²x² - 3ax + 3ax - 9
Cancelling - 3x and + 3x
= a²x² - 9
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Answered by
0
Answer:
ax²- 9
Step-by-step explanation:
(ax+3)(ax-3)
By using (x+y)(x-y)= x²- y²
where x=ax and y=3
Therefore by substituting the values we get,
(ax+3)(ax-3)= ax²- 3²
= ax²- 9
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