Question

multiply each number of the sequence 123...by 3 and add 2 then write the resulting numbers as a sequence

Answer 1

(1 \times× 3) + 2, (2 \times× 3) + 2, (3 \times× 3) + 2, (4 \times× 3) +

First term = a = 5

Common difference = d = 3

(a) The tenth term of this sequence is given by;

             a_n = a + (n -1) dan=a+(n−1)d  

             a_1_0 = 5 + (10 -1) \times 3

                    = 5 + 27 = 32

                   a_n = a + (n -1) dan=a+(n−1)d  

                    98 = 5 + (n -1) \times 398=5+(n−1)×3

                    98 -5= 3n-398−5=3n−3

                    3(n-1) = 933(n−1)=93

                    n-1 = \frac{93}{3}n−1=393

                    n = 31 + 1 = 32