Math, asked by amritapriyadar97, 1 day ago

Multiply -
(i) (13a^2b - 7abc + 15 b^2c) by 4abc -

Answers

Answered by itsmesanyo29
51

 \bold { \red{SOLUTION: }}

GIVEN :

 \implies {\mathtt{13a^2b - 7abc + 15 b^2c \times (4abc)}}

ANSWER:

 \implies {\mathtt{13a^2b - 7abc + 15 b^2c \times (4abc)}}

Hence,

Multiplying the values

 \implies {\mathtt{13a^2b  \times(4abc) - 7abc  \times(4abc) + 15 b^2c \times (4abc) }} \\

  \implies { \mathtt{52 {a}^{3}  {b}^{2} c - 28 {a}^{2}  {b}^{2}  {c}^{2} +60a {b}^{3}  {c}^{2} }}

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Answered by minishapranishaagraw
0

Answer:

Here, is your answer I hope it will help you

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