Multiply multiplicative inverse and additive inverse of 3 integer 1/7
Answers
Answered by
10
Here, the number is
3
So, multiplicative inverse of 22/7 is
= 1/(22/7)
= 7/22
and additive inverse of 22/7 is
= - 22/7
Therefore, product of multiplicative inverse and additive inverse of 22/7 is
= (7/22) × (- 22/7)
=
#
Answered by
8
hay dear
Solution -
Given that =>

Now, multiplicative inverse = 7/22
and additive inverse = -22/7
then,

= -1
I hope it's help you
Regards : Sangela
Solution -
Given that =>
Now, multiplicative inverse = 7/22
and additive inverse = -22/7
then,
= -1
I hope it's help you
Regards : Sangela
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