Question

multiply (root2+root3) and (2root5+7root3)

Answer 1

ѧṅśwєя :

$= > ( \sqrt{2} + \sqrt{3} )(2 \sqrt{5} + 7 \sqrt{3} ) \\ \\ take \: the \: first \: term \: i.e. \sqrt{2} \: and \: multiply \: it \: with \: the \: terms \: in \: the \: second \: bracket. \\ \\ = > \sqrt{2} (2 \sqrt{5} + 7 \sqrt{3} ) \\ \\ then \: take \: the \: second \: term \: i.e. \sqrt{3} \: and \: multiply \: it \: with \: the \: terms \: in \: other \: bracket. \\ \\ = > \sqrt{3} (2 \sqrt{5} + 7 \sqrt{3} ) \\ \\ now \: take \: it \: together \: and \: multiply \\ \\ = > \sqrt{2} (2 \sqrt{5} + 7 \sqrt{3} ) + \sqrt{3} (2 \sqrt{5} + 7 \sqrt{3} ) \\ \\ = > 2 \sqrt{2 \times 5} + 7 \sqrt{2 \times 3} + 2 \sqrt{3 \times 5} + 7 \sqrt{3 \times 3} \\ \\ = > 2 \sqrt{10} + 7 \sqrt{6} + 2 \sqrt{15} + 7 \times 3 \\ \\ = > 2 \sqrt{10} + 7 \sqrt{6} + 2 \sqrt{15} + 21 \\ \\ = > 21 + 2 \sqrt{15} + 2 \sqrt{10} + 7 \sqrt{6}$

ṭʏśṃ ғȏя ṭһє զȗєśṭıȏṅ!

Answer 2

✨✨hlo here isyour ans✨✨