Math, asked by surchandraokram545, 1 month ago

Multiply


Root2+root5+root7 by root2+root5-root7

Answers

Answered by adityaraj5850
1

Answer:

( \sqrt{2}   +  \sqrt{5}  +  \sqrt{7} ) \times ( \sqrt{2}  +  \sqrt{5}  -  \sqrt{7} ) \\ ( \sqrt{2}  +  \sqrt{5} )^{2}  -   { \sqrt{7} }^{2} \\ 2 + 5 + 2 \sqrt{10}  - 7 \\ 7 - 7 + 2 \sqrt{10}  \\ 2 \sqrt{10}

Step-by-step explanation:

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Answered by PrakharSinghal
0

Answer:

2√10

Step-by-step explanation:

(√2+√5+√7)×(√2+√5-√7)

= (√2+√5)^2 - (√7)^2.

{ use (a+b)(a-b)=a^2-b^2 }

= 2+5+2√10-7

= 2√10

Hope it helps :)

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