Question

multiply the additive inverse of [2/3-(-4/9)]with the reciprocal of [3/9-(-7/2]....... please give me the answer 1:20..
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Answer 1

Answer:

- 20/23

Step-by-step explanation:

Given multiply the additive inverse of [2/3-(-4/9)]with the reciprocal of [3/9-(-7/2].......

Now we need to find 2/3 - (- 4/9) = 2/3 + 4/9 = 10/9

Also 3/9 - (-7/2) = 3/9 + 7/2 = 23/6

Now we need to find the additive inverse of 10/9 which is equal to - 10/9

and reciprocal of 23/6 is 6/23

So multiplying both the fractions we get

- 10/9 x 6/23 = - 20/23