multiply the binomial (2pq+3q²) and 3(3pq-2q²)
from class 8.
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Ur Answer :-
(2pq+3q²) (3pq-2q²)
= 2pq(3pq - 2q²) + 3p²(3pq - 2q²)
= (2pq × 3pq) - (2pq × 2q² ) + (3p² × 3pq) - (3q² × 2q²)
= 6p²q² - 4p³ + 9pq³ - 6q⁴
= 6p²q² + 5pq³ - 6q⁴
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