Multiply the binomial (n+m)(2n-3m)
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If sin A + cos A = m and
sin3A+cos3A=nsin3A+cos3A=n,
then (1) m3-3m+n=0m3-3m+n=0
(2) n3-3n+2m-On3-3n+2m=0 (3)
m3-3m+2n=0m3-3m+2n=0 (4)
m3+3m+2n=0
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