Question

multiply the binomials. (2pq+3q2) and (3pq_2q2)​

Answer 1

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$(2pq + 3 {q}^{2}) \times (3pq - 2 {q}^{2}) \\ = 2pq(3pq - 2 {q}^{2}) + 3 {q}^{2}(3pq - 2 {q}^{2}) \\ = 6 {p}^{2} {q}^{2} - 4p {q}^{3} + 9p {q}^{3} - 6 {q}^{4} \\ = 6 {p}^{2} {q}^{2} + 5p {q}^{3} - 6 {q}^{4}$

Answer 2

(2pq+3q²)×(3pq-2q²)

= 2pq(3pq-2q²)+3q²(3pq-2q²)

=6p²q²-4pq³+9pq³-6q4

=6p²q²+5pq³-6q4