multiply the binomials
(3/4a² +3b²)×4(a²-2/3)
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Step-by-step explanation:
the formula of a+b a-b is a²-b²
so as for question
(3a²/4+3b²)×4(a²-8/3). = (3a²/4+3b²)×(4a²-24/3)
*first - into both the a with each other
3a²/4×4a² = 12a²/4a² it can be cancel by the table of 4 than it will be 3a²
*second step - multiply both the b
which will be 3b²×24/3 = 24b²
now apply the formula
a²-b² = 3a²-24b²
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