Question

Multiply the binomials and verify the result for the given values:

(0.1p+0.2q)(0 2q-0.1p);p=10,q=3​

Answer 1

Step-by-step explanation:

[0.1(10)+0.2(3)][0.2(3)-0.1(10)]

(1+0.6).( 0.6-1) =(1.6)(-0.4) =0.64

its you answer

and please mark me as brainiest....

i hope my answer will be correct

Answer 2

Answer:

Step-by-step explanation:

let z=(0.1p+0.2q) (0 2q-0.1p)........(1)

=(p*1/10+2q/10) (2q/10-p/10)

=(p/10+q/5)(q/5-p/10)

=q²/25--p²/100............(1)

Putting p=10 and q=3 in (1)

z=(10/10+0.2*3)(0.2*3-10/10)

=(1+0.6) (0.6-1)

=1.6*(-0.4)= -0.64

***********************

putting p=10 and q=3 in(2)

z=9/25-100/100

=36/25-100/100=-64/10=-0.64

Both are qequal to -0.64 \hence verufied