Question

multiply the binomials (y-8) and (3y-4)​

Answer 1

Answer:

$(y - 8) + \times (3y - 4)$

$3y^{2} - 4y - 24y - + 32$

${3y}^{2} - 28y + 32$

Answer 2

The correct answer is "3y²-28y+32".

Step-by-step explanation:

$The \ given \ binomials \ are:\\\\(y-8) \ and \ (3y-4)\\\\On \ applying \ multiplication,we \ get\\\\=y(3y-4)-8(3y-4)\\\\=3y^2-4y-24y+32\\\\=3y^2-28y+32$

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https://brainly.in/question/13974132