Question

Multiply the following
3x-5z by 2y-4z
can somebody please tell it fast and explain it a bit long ​

Answer 1

Question :-

Multiply the Following :- (3x - 5z) by (2y - 4z)

Solution :-

By using the Distributive Law of Multiplication over Subtraction twice, we get their Product as -

$\begin {aligned} \bold {(3x - 5z)(2y - 4z)} & = 3x \times (2y - 4z) + (-5z)\times (2y - 4z)\\\\& \Rightarrow 6xy - 12xz + (-10yz) + 20z^2\\\\& = \bold {6xy - 12xz - 10yz + 20z^2} \end {aligned}$

This Method is also known as the Horizontal Method.

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Answer 2

Step-by-step explanation:

Question :-

Multiply the Following :- (3x - 5z) by (2y - 4z)

Solution :-

By using the Distributive Law of Multiplication over Subtraction twice, we get their Product as -

\begin{gathered}\begin {aligned} \bold {(3x - 5z)(2y - 4z)} & = 3x \times (2y - 4z) + (-5z)\times (2y - 4z)\\\\& \Rightarrow 6xy - 12xz + (-10yz) + 20z^2\\\\& = \bold {6xy - 12xz - 10yz + 20z^2} \end {aligned}\end{gathered}

(3x−5z)(2y−4z)

=3x×(2y−4z)+(−5z)×(2y−4z)

⇒6xy−12xz+(−10yz)+20z

2

=6xy−12xz−10yz+20z

2

This Method is also known as the Horizontal Method.

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#HappyLearning!