Question

multiply the following:
(7ab^2);(4a^4b^3)​

Answer 1

Step-by-step explanation:

$7a {b}^{2} \times 4 {a}^{4} {b}^{3} \\ = > 28 {a}^{5} {b}^{5}$

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Answer 2

Answer:

${28a}^{5} {b}^{5}$

Explanation :-

$7ab {}^{2} \times 4a {}^{4} b {}^{3} \\(7 \times 4) \times (a {}^{1} \times a {}^{4} + b {}^{2} \times b {}^{3} ) \\ 28 \times a {}^{5} b {}^{5} \\ 28a {}^{5b {}^{5} }$

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