Math, asked by pa932630, 11 months ago

multiply the following algebraic expressions (a+d)&(a-d),(2x+3)(x-4), (x-5)(x-7),(x-2)(6x-3)​

Answers

Answered by klmazad
1

Answer:

(a+d)(a-d) = a^2-b^2

(2x+3)(x-4) = 2x^2 -5x -12

(x-5)(x-7)= x^2-12x+35

(x-2)(6x-3) = 6x^2 -15x +6

Step-by-step explanation:

Answered by SerenaBochenek
0

The correct answers are:

1...a²-d²

2...2x²-5x-12

3...x²-12x+35

4...6x²-15+6

Step-by-step explanation:

The \ given \ expressions \ are:\\\\1...\\=(a+d)(a-d)\\On \ applying \ multiplication,we \ get\\=a(a-d)+d(a-d)\\=a^2-ad+ad-d^2\\=a^2-d^2\\\\2...\\=(2x+3)(x-4)\\On \ applying \ multiplication,we \ get\\=x(2x+3)-4(2x+3)\\=2x^2+3x-8x-12\\=2x^2-5x-12\\\\3...\\=(x-5)(x-7)\\On \ applying \ multiplication,we \ get\\=x(x-7)-5(x-7)\\=x^2-7x-5x+35\\=x^2-12x+35\\\\4...\\=(x-2)(6x-3)\\=On \ applying \ multiplication,we \ get\\=x(6x-3)-2(6x-3)\\=6x^2-3x-12x+6\\=6x^2-15x+6

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