multiply the following and verify the result by taking a =-1 b=2 c=1 (3a+2b+c)(2a²-5ab+b²)
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67
Step-by-step explanation:
3a(2a²-5ab+b²)+2b(2a²-5ab+b²)+c(2a²-5ab+b²)
3a³-15a²b+3ab²+4a²b-10ab²+2b³+2a²c-5abc+b²c
3a³-11a²b-7ab²+2b³+2a²c-5abc+b²c
substituting a=-1, b=2 and c=3
3(-1³)-11(-1²)(2)-7(-1)(2²)+2(2³)+2(-1²)(3)-5(-1)(2)(3)+(2²)(3)
-3-22+28+16+6+30+12
67
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