Question

multiply the following binomial expression
(3/2x²+2/3y³) and (2x²-3y²)​

Answer 1

Step-by-step explanation:

multiply the following binomial expression

(3/2x²+2/3y³) and (2x²-3y²)

(6xy) × (-3x²y³)

= {6 × (-3)} × {xy × x²y³}

= -18x1+2 y1+3

= -18x³y⁴.

(-3x²y) × (4x²y - 3xy² + 4x - 5y)

= (-3x²y) × (4x²y) + (-3x²y) × (-3xy²) + (-3x²y) × (4x) + (-3x²y) × (-5y)

= -12x⁴y² + 9x³y³ - 12x³y + 15x²y².

(7ab²) × (-4a²b) × (-5abc)

= {7 × (-4) × (-5)} × {ab² × a²b × abc}

= 140 a1+2+1 b2+1+1 c

= 140a⁴b⁴c.

5a²b² × (3a² - 4ab + 6b²)

= (5a²b²) × (3a²) + (5a²b²) × (-4ab) + (5a²b²) × (6b²)

= 15a⁴b² - 20a³b³ + 30a²b⁴.