multiply the following binomial expression
(3/2x²+2/3y³) and (2x²-3y²)
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Answer:
Equation:
(3/2x-2/3y)(3/2x-2/3y)
To find:
(3/2x-2/3y)(3/2x-2/3y)
=(3/2x)^2(-2/3y)^2
=9/4x^2+2/3y^2
Hence Answer:
9/4x^2+2/3y^2
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