Multiply the following binomial of (7x^2+4y^2)(3x^2+8y^2)
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Step-by-step explanation:
(7x²+4y²)(3x²+8y²)
= 7x²(3x²+8y²)+4y²(3x²+8y²)
= 21x⁴+56x²y²+12x²y²+32y⁴
= 21x⁴+68x²y²+32y⁴
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