Math, asked by kumar252695, 2 months ago

Multiply the following:
(i) 5x² - 4x + 1 by 2x² + 3x - 7

Answers

Answered by mishrashaily57
0

Step-by-step explanation:

ANSWER:=(5x^2+3x-7)(x-1)-(2x^2+3x-4)(2x-3)=(5x^3+3x^2-7x-5x^2-3x+7)-(4x^3+3x^2-8x-6x^2-9x+12)=(5x^3-2x^2-10x+7)-(4x^3-3x^2-17x+12)=x^3-5x^2-27x+19

Answered by vidhyabarud
5

( {5x}^{2}  - 4x + 1) \times ( {2x}^{2}  + 3x - 7) \\  {5x}^{2} ( {2x}^{2}  + 3x - 7) - 4x({2x}^{2}  + 3x - 7) + 1({2x}^{2}  + 3x - 7) \\  {10x}^{4}  +  {15x}^{3}  -  {35x}^{2}  -  {8x}^{3}  -  {12x}^{2}  + 28x + {2x}^{2}  + 3x - 7 \\  {10x}^{4}  +  {15x}^{3}  -  {8x}^{3}  -  {35x}^{2}  -  {12x}^{2}  +  {2x}^{2}  + 28x + 3x - 7 \\  {10x}^{4}  +  {7x}^{3}  -  {45x}^{2} + 31x - 7 \\  \\  \\  \\

Hope Helps You ✌️

Please mark as the Brainliest ‼️

Similar questions