Question

Multiply the following polynomials: (3x2-2x+5) (2x+3)​

Answer 1

To find:

(3x²-2x+5)(2x+3)

$(3x^{2}-2x+5)(2x+3)\\= 2x(3x^{2}-2x+5)+3(3x^{2}-2x+5)\\= 6x^{3}-4x^{2}+10x+9x^{2}-6x+15\\= 6x^{3}+9x^{2}-4x^{2}+10x-6x+15\\= \bf \underline{6x^{3}+5x^{2}+4x+15}$

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Answer 2

ANS - $\boxed{ \red{ 6x³ + 5x² + 4x + 15 }}$

On multiplying ,

(3x² - 2x + 5 )( 2x + 3 )

$\red{ \implies}$ 3x²(2x) -2x(2x) + 5(2x) + 3x²(3) -2x(3) + 5(3)

$\red{ \implies}$ 6x³ - 4x² + 10x + 9x² - 6x + 15

$\red{ \implies}$ 6x³ + 5x² + 4x + 15

$\rule{10cm}{0.05cm}$

Ie , Ans = 6x³ + 5x² + 4x + 15