multiply the following product monomial by trinomials (3a +5) by (4/5b² + 3b - 1)
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Answer:
−5b2×(5b2+3b−14)
= \frac{ - 20 {b}^{2} }{5 {b}^{2} + 3b - 1}=5b2+3b−1−20b2
the question is different but solution is same
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Answer:
12 a+20/ 5b²+3b-1 Answer.
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