Question

Multiply the reciprocal of 9/11 by the additive inverse of -18/55

Answer 1

= 11/9 * 18/55

= 11 * 18 / 9 * 55

= 2/5

Answer 2

Answer:

• The product of reciprocal of 9/11 and additive inverse of -18/55 is 2/5.

Step-by-step explanation:

To solve this we first need to know what is reciprocal and additive inverse.

• Every nonzero rational number a/b has its reciprocal b/a. So that,

$\sf{\circ\;\dfrac{a}{b}\times\dfrac{b}{a}=\dfrac{b}{a}\times\dfrac{a}{b}=1}$

• Every rational number a/b (or -a/b), there is a additive inverse -a/b (or a/b). So that,

$\sf{\circ\;\dfrac{a}{b}+\dfrac{-a}{b}=0}$

So,

$\sf{\circ\;Reciprocal\;of\;\dfrac{9}{11}=\dfrac{11}{9}}$

$\sf{\circ\;Additive \;inverse \;of \;\dfrac{-18}{55}=\dfrac{18}{55}}$

Now,

According to the question we have to multiply 11/9 by 18/55.

$\sf{\longmapsto\dfrac{11}{9}\times\dfrac{18}{55}}$

Reducing the numbers,

$\sf{\longmapsto\dfrac{1}{1}\times\dfrac{2}{5}}$

Multiplying the numbers,

$\sf{\longmapsto\dfrac{2}{5}}$

Hence,

• The product 11/9 and 18/55 is 2/5.