Question

multiply the term x power 3 y power 3 × [-3/2 (x-y) ]​

Answer 1

question:

x^3y^3[-3/2(x-y)]

To find:

find the product x^3y^3[-3/2(x-y)]

Solution:

From given, we have,

x^3y^3[-3/2(x-y)]

\begin{gathered}x^3y^3\left(-\frac{3}{2}\left(x-y\right)\right)\\\\=\left(xy\right)^3\left(-\frac{3}{2}\left(x-y\right)\right)\\\\=-\left(xy\right)^3\frac{3}{2}\left(x-y\right)\\\\=-\left(x-y\right)\frac{3\left(xy\right)^3}{2}\\\\=-\frac{3x^3y^3}{2}\left(x-y\right)\end{gathered}

x

3

y

3

(−

2

3

(x−y))=(xy) 3(− 23 (x−y))=−(xy) 3

2

3

(x−y)

=−(x−y)

2

3(xy)

3

=−

2

3x

3

y

3

(x−y)

∴ x^3y^3[-3/2(x-y)] = -[3x³y³/2](x - y)